Ebook IB Math AA & AI HL/SL | Chinh Phục 7 - Times Edu
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IB Mathematics
AA & AI
Practice Papers & Solutions
Number · Algebra Functions Trigonometry Calculus Statistics · Probability SL + HL
30+ Worked problems
5 Topics covered
Song ngữ Anh–Việt
00
Overview
Giới thiệu IB Mathematics

IB Mathematics có hai lộ trình chính: AA (Analysis & Approaches)AI (Applications & Interpretation). Mỗi lộ trình phù hợp với định hướng học thuật và nghề nghiệp khác nhau.

AA · Analysis & Approaches

Focus: Pure maths, proof, algebra

SL Papers: P1 (no calc, 1h30m) + P2 (calc, 1h30m)

HL Papers: P1 (no calc, 2h) + P2 (calc, 2h) + P3 (1h)

Best for: Engineering, Physics, Pure Maths

AI · Applications & Interpretation

Focus: Real-world, statistics, modelling

SL Papers: P1 (no calc, 1h30m) + P2 (calc, 1h30m)

HL Papers: P1 (no calc, 1h30m) + P2 (calc, 1h30m) + P3 (1h)

Best for: Business, Social Sciences, Biology

Mẹo đạt điểm 7
  • Formula booklet: Học cách TRA NHANH — không cần thuộc hết (booklet được cung cấp trong phòng thi)
  • Paper 1 (no calc): Luyện tính tay, exact values, fractions
  • Show working: Mỗi bước = marks. Không nhảy bước!
  • GDC skills: Graph, solve, regression, normal distribution
  • Read mark scheme: Hiểu cách chấm để biết cần viết gì
  • Mark types: [M] marks = method · [A] marks = answer · [R] marks = reasoning
Tiêu chí AA (Analysis & Approaches) AI (Applications & Interpretation)
Focus Pure maths, proof, algebra Real-world, statistics, modelling
Calculator GDC cho P2 & P3 GDC cho P2 & P3
IA Mathematical exploration (12–20 pages) Mathematical exploration (same)
Best for Engineering, Physics, Pure Maths Business, Social Sciences, Biology

01
Topic 1
Number & Algebra
1.1 · Sequences & Series
Arithmetic Progression (AP)
uₙ = u₁ + (n−1)d
Sₙ = n/2 · (2u₁ + (n−1)d)
Sₙ = n/2 · (u₁ + uₙ)
Geometric Progression (GP)
uₙ = u₁ · rⁿ⁻¹
Sₙ = u₁(1−rⁿ)/(1−r)
S∞ = u₁/(1−r) [|r| < 1]
Sigma Notation (HL)
∑[r=1→n] r = n(n+1)/2
∑ r² = n(n+1)(2n+1)/6
Binomial Theorem
(a+b)ⁿ = ∑ C(n,r) · aⁿ⁻ʳ · bʳ
C(n,r) = n! / (r!(n−r)!)
Tᵣ₊₁ = C(n,r) · aⁿ⁻ʳ · bʳ
Dùng để tìm hệ số của xᵏ trong khai triển đa thức
Exponents & Logarithms
aˣ = b ⟺ x = logₐ b
log(ab) = log a + log b
log(a/b) = log a − log b
log(aⁿ) = n log a
logₐ b = ln b / ln a
ln eˣ = x · e^(ln x) = x
Complex Numbers — AA HL only
z = a + bi
|z| = √(a²+b²)
arg(z) = arctan(b/a)
Polar: z = r cisθ = re^(iθ)
De Moivre: (r cisθ)ⁿ = rⁿ cis(nθ)
Practice Questions
AA SL 5 marks
Q1 · Arithmetic Progression

AP: u₃ = 11, u₇ = 23. Tìm u₁, d, và S₂₀.

✓ Solution
u₃ = u₁ + 2d = 11
u₇ = u₁ + 6d = 23
Trừ: 4d = 12  →  d = 3
u₁ = 11 − 6 = 5

S₂₀ = 20/2 · (2×5 + 19×3)
     = 10 · (10 + 57)
     = 10 × 67
     = 670
AI SL 6 marks
Q2 · Geometric Progression

GP: u₁ = 200, r = 0.85.
(a) Tìm u₅.  (b) Tìm n nhỏ nhất sao cho uₙ < 50.  (c) Tìm S∞.

✓ Solution
(a) u₅ = 200(0.85)⁴ = 200 × 0.522 = 104.4

(b) 200(0.85)ⁿ⁻¹ < 50
    0.85ⁿ⁻¹ < 0.25
    (n−1)ln 0.85 < ln 0.25
    n−1 > ln 0.25 / ln 0.85 = 8.53
    ∴ n ≥ 10

(c) S∞ = 200 / (1 − 0.85) = 200 / 0.15 = 1333.33
AA HL 6 marks
Q3 · Binomial Theorem

Tìm hệ số của x³ trong khai triển (2x − 1)⁷.

✓ Solution
Tᵣ₊₁ = C(7,r)(2x)⁷⁻ʳ(−1)ʳ

Cần power của x = 3  →  7 − r = 3  →  r = 4

T₅ = C(7,4)(2x)³(−1)⁴
   = 35 × 8x³ × 1
   = 280x³

∴ Hệ số: 280

02
Topic 2
Functions
2.1 · Key Concepts

Domain: Tập xác định (input) · Range: Tập giá trị (output)

Inverse f⁻¹: Hoán đổi x và y, giải tìm y. Đồ thị: phản chiếu qua y = x. Tính chất: f(f⁻¹(x)) = x

Composite fg: fg(x) = f(g(x)) — Thực hiện g trước, sau đó f

2.2 · Transformations
Graph Transformations
f(x) + a → dịch lên a
f(x − a) → dịch phải a
af(x) → giãn dọc ×a
f(ax) → co ngang ×1/a
−f(x) → phản chiếu Ox
f(−x) → phản chiếu Oy
2.3 · Types of Functions
Common Function Types
Quadratic: f(x) = ax²+bx+c · Vertex: (−b/2a, f(−b/2a)) · Δ = b²−4ac
Exponential: f(x) = kaˣ + c · Asymptote y=c · Growth a>1 · Decay 0<a<1
Logarithmic: f(x) = logₐ(x) · Inverse của exponential · Domain: x>0
Rational (HL): f(x) = (ax+b)/(cx+d) · VA: x=−d/c · HA: y=a/c
Practice Questions
AA/AI SL 5 marks
Q4 · Quadratic Function

f(x) = 3(x−2)² + 5. Tìm: (a) Vertex. (b) Axis of symmetry. (c) y-intercept. (d) Range.

✓ Solution
(a) Vertex: (2, 5)
(b) Axis of symmetry: x = 2
(c) f(0) = 3(4) + 5 = 17  →  y-intercept: (0, 17)
(d) Range: y ≥ 5
AA SL 6 marks
Q5 · Composite & Inverse Functions

f(x) = 2x+1, g(x) = x²−3. Tìm: (a) fg(x). (b) gf(x). (c) f⁻¹(x).

✓ Solution
(a) fg(x) = f(x²−3) = 2(x²−3)+1 = 2x² − 5

(b) gf(x) = g(2x+1) = (2x+1)²−3
          = 4x²+4x+1−3
          = 4x²+4x−2

(c) y = 2x+1  →  x = (y−1)/2
    ∴ f⁻¹(x) = (x−1)/2
AI SL 5 marks
Q6 · Exponential Growth Model

Model: P = 500e^(0.03t). (a) P ban đầu. (b) P sau 10 năm. (c) Thời gian để P gấp đôi.

✓ Solution
(a) P(0) = 500

(b) P(10) = 500e^0.3 = 500 × 1.3499 ≈ 675

(c) 1000 = 500e^(0.03t)
    2 = e^(0.03t)
    ln 2 = 0.03t
    t = ln 2 / 0.03 ≈ 23.1 năm

03
Topic 3
Geometry & Trigonometry
3.1 · Trigonometry
Core Identities & Rules
sin²θ + cos²θ = 1
tanθ = sinθ/cosθ
Sine rule: a/sinA = b/sinB = c/sinC
Cosine rule: c² = a²+b²−2ab cosC
Area = ½ab sinC
Arc: s = rθ · Sector: A = ½r²θ
Compound Angle Identities — AA
sin(A±B) = sinA cosB ± cosA sinB
cos(A±B) = cosA cosB ∓ sinA sinB
sin 2A = 2 sinA cosA
cos 2A = cos²A − sin²A
cos 2A = 2cos²A − 1
cos 2A = 1 − 2sin²A
Vectors — AA & AI
|v| = √(x²+y²+z²)
v̂ = v/|v|
a·b = |a||b|cosθ
a·b = a₁b₁+a₂b₂+a₃b₃
Line: r = a + t·d
Angle: cosθ = |d₁·d₂| / (|d₁||d₂|)
Practice Questions
AA/AI SL 6 marks
Q7 · Cosine Rule & Area

Tam giác: a = 8, b = 5, C = 60°. Tìm c và diện tích.

✓ Solution
c² = a² + b² − 2ab cosC
   = 64 + 25 − 80 cos 60°
   = 89 − 40 = 49
   c = 7

Area = ½(8)(5) sin 60°
     = 20 × (√3/2)
     = 10√3 ≈ 17.3
AA SL 5 marks
Q8 · Trig Equation

Giải: 2sin²x − sinx − 1 = 0,   0 ≤ x ≤ 2π.

✓ Solution
Đặt t = sinx:  2t² − t − 1 = 0
(2t + 1)(t − 1) = 0
t = −1/2  hoặc  t = 1

sinx = 1:    x = π/2
sinx = −1/2: x = 7π/6,  11π/6

∴ Nghiệm: x = π/2,  7π/6,  11π/6
AA/AI SL 5 marks
Q9 · Dot Product & Angle

a = (2, 1, −3), b = (1, −2, 4). Tìm a·b và góc giữa a và b.

✓ Solution
a·b = 2(1) + 1(−2) + (−3)(4) = 2−2−12 = −12

|a| = √(4+1+9) = √14
|b| = √(1+4+16) = √21

cosθ = −12 / (√14 × √21) = −12 / √294 = −0.6993

θ = arccos(−0.6993) ≈ 134.4°

04
Topic 4
Statistics & Probability
4.1 · Descriptive Statistics
Measures of Centre & Spread
Mean μ = ∑x/n
Var σ² = ∑(x−μ)²/n
SD = √Variance
IQR = Q₃ − Q₁
Correlation r (Pearson's): −1 ≤ r ≤ 1. Gần ±1: strong. Gần 0: weak. Regression y = ax+b: dùng GDC; chỉ dự đoán trong range dữ liệu
4.2 · Probability
Probability Rules
P(A∪B) = P(A) + P(B) − P(A∩B)
P(A|B) = P(A∩B) / P(B)
Independent: P(A∩B) = P(A)×P(B)
Mut. exclusive: P(A∩B) = 0
4.3 · Distributions
Binomial X ~ B(n, p)
P(X=k) = C(n,k) · pᵏ · (1−p)ⁿ⁻ᵏ
E(X) = np
Var(X) = np(1−p)
Normal X ~ N(μ, σ²)
Z = (X − μ)/σ
P(X < a) = P(Z < (a−μ)/σ)
GDC: normalcdf(lower, upper, μ, σ)
GDC: invNorm(area, μ, σ)
Poisson X ~ Po(λ) — AI HL
P(X=k) = e⁻λ · λᵏ / k!
E(X) = Var(X) = λ
Practice Questions
AI SL 6 marks
Q10 · Normal Distribution

X ~ N(170, 8²). (a) P(X > 180). (b) Tìm k sao cho P(X < k) = 0.3.

✓ Solution
(a) Z = (180−170)/8 = 1.25
    P(Z > 1.25) = 1 − 0.8944 = 0.1056

(b) invNorm(0.3, 170, 8)
  = 170 + 8 × (−0.5244)
  = 170 − 4.195
  = 165.8
AA/AI SL 5 marks
Q11 · Binomial Distribution

X ~ B(8, 0.4). Tìm P(X = 3) và P(X ≥ 2).

✓ Solution
P(X=3) = C(8,3)(0.4)³(0.6)⁵
       = 56 × 0.064 × 0.07776
       = 0.2787

P(X≥2) = 1 − P(X=0) − P(X=1)
       = 1 − (0.6)⁸ − 8(0.4)(0.6)⁷
       = 1 − 0.01680 − 0.08958
       = 0.8936
AI SL 4 marks
Q12 · Conditional Probability

P(A) = 0.6, P(B|A) = 0.3, P(B|A') = 0.5. Tìm P(B).

✓ Solution
P(B) = P(B|A)·P(A) + P(B|A')·P(A')
     = 0.3(0.6) + 0.5(0.4)
     = 0.18 + 0.20
     = 0.38

05
Topic 5
Calculus
5.1 · Differentiation
Standard Derivatives
d/dx [xⁿ] = nxⁿ⁻¹
d/dx [eˣ] = eˣ
d/dx [ln x] = 1/x
d/dx [sin x] = cos x
d/dx [cos x] = −sin x
d/dx [tan x] = sec²x
Differentiation Rules
Chain: f'(g(x)) · g'(x)
Product: (uv)' = u'v + uv'
Quotient: (u/v)' = (u'v−uv')/v²
Applications:
Tangent: y−y₁ = f'(x₁)(x−x₁)
Normal: m = −1/f'(x₁)
f'=0 → critical pts
5.2 · Integration
Standard Integrals
∫ xⁿ dx = xⁿ⁺¹/(n+1) + C
∫ eˣ dx = eˣ + C
∫ 1/x dx = ln|x| + C
∫ sin x dx = −cos x + C
∫ cos x dx = sin x + C
Applications
FTC: ∫[a→b] f dx = F(b)−F(a)
Area: ∫|f(x)−g(x)| dx
Volume: π∫y² dx (Ox)
HL only:
Parts: ∫u dv = uv − ∫v du
Maclaurin series
Diff equations (sep.)
Practice Questions
AA SL 5 marks
Q13 · Tangent Line

f(x) = x³ − 3x + 2. Tìm phương trình tiếp tuyến tại x = 1.

✓ Solution
f'(x) = 3x² − 3
f'(1) = 3 − 3 = 0

f(1) = 1 − 3 + 2 = 0 → Point: (1, 0)

Tangent: y − 0 = 0(x − 1)
∴ y = 0  (đường nằm ngang)
AA SL 6 marks
Q14 · Area Between Curves

Tìm diện tích giữa y = x² và y = 2x từ x = 0 đến x = 2.

✓ Solution
Area = ∫₀² |2x − x²| dx  [2x ≥ x² trên [0,2]]
     = ∫₀² (2x − x²) dx
     = [x² − x³/3]₀²
     = (4 − 8/3) − 0
     = 4 − 2.667
     = 4/3 ≈ 1.33
AI SL 6 marks
Q15 · Kinematics

v(t) = 3t² − 12t + 9. (a) Khi nào vật dừng? (b) Displacement từ t=0 đến t=3.

✓ Solution
(a) v = 0: 3t²−12t+9 = 3(t−1)(t−3) = 0
    t = 1s  và  t = 3s

(b) s = ∫₀³ (3t²−12t+9) dt
     = [t³ − 6t² + 9t]₀³
     = (27 − 54 + 27) − 0
     = 0

∴ Displacement = 0 (vật trở về vị trí ban đầu)
AA HL 6 marks
Q16 · Integration by Parts

Tính ∫ x² ln x dx

✓ Solution
Đặt: u = ln x  →  du = 1/x dx
     dv = x² dx  →  v = x³/3

∫ x² ln x dx = (x³/3) ln x − ∫ (x³/3)(1/x) dx
             = (x³/3) ln x − ∫ x²/3 dx
             = (x³/3) ln x − x³/9 + C
AA HL 7 marks
Q17 · Differential Equation

Giải DE: dy/dx = 2xy, y(0) = 1. Tìm particular solution.

✓ Solution
Separable:
∫ dy/y = ∫ 2x dx
ln|y| = x² + C
y = Ae^(x²)

Apply y(0) = 1:  A = 1

∴ y = e^(x²)

06
Mixed Practice
Mixed Practice Paper
!
Exam Conditions

Simulate exam conditions: Paper 1 (no calculator), Paper 2 (calculator allowed). Time yourself and show full working.

Paper 1 Style — No Calculator
P1 4 marks
Q18 · Logarithms

Simplify: log₂ 8 + log₂ 4 − log₂ 2.

✓ Solution
log₂ 8 = 3  (vì 2³ = 8)
log₂ 4 = 2  (vì 2² = 4)
log₂ 2 = 1  (vì 2¹ = 2)

Kết quả: 3 + 2 − 1 = 4
P1 5 marks
Q19 · Exact Integration

Tìm exact value: ∫₀^(π/3) (2cos x − sin x) dx.

✓ Solution
= [2sin x + cos x]₀^(π/3)
= (2 sin(π/3) + cos(π/3)) − (2·0 + 1)
= (2·(√3/2) + 1/2) − 1
= (√3 + 1/2) − 1
= √3 − 1/2
P1 5 marks
Q20 · Exponential Equation

f(x) = e^(2x) − 4eˣ. Tìm x khi f(x) = 0.

✓ Solution
e^(2x) − 4eˣ = 0
eˣ(eˣ − 4) = 0

eˣ > 0 luôn luôn  →  eˣ = 4
x = ln 4 = 2 ln 2
P1 6 marks
Q21 · Trig Proof

Chứng minh: (1 + tan²θ)(1 − sin²θ) = 1.

✓ Solution
LHS = (1 + tan²θ)(1 − sin²θ)

(1 + tan²θ) = sec²θ
(1 − sin²θ) = cos²θ

∴ LHS = sec²θ × cos²θ
       = (1/cos²θ) × cos²θ
       = 1 = RHS  ■
Paper 2 Style — Calculator Allowed
P2 6 marks
Q22 · Normal Distribution

X ~ N(500, 40²). (a) P(450 < X < 550). (b) 95th percentile.

✓ Solution
(a) GDC: normalcdf(450, 550, 500, 40)
    = P(−1.25 < Z < 1.25)
    = 0.7887

(b) GDC: invNorm(0.95, 500, 40)
    = 500 + 40(1.645)
    = 565.8
P2 7 marks
Q23 · Optimisation

Hình hộp chữ nhật không nắp, thể tích 32 cm³. Đáy vuông cạnh x. Tìm x để diện tích bề mặt nhỏ nhất.

✓ Solution
V = x²h = 32  →  h = 32/x²

S = x² + 4xh = x² + 4x(32/x²) = x² + 128/x

dS/dx = 2x − 128/x² = 0
2x³ = 128  →  x³ = 64  →  x = 4 cm

d²S/dx² = 2 + 256/x³ = 6 > 0 at x=4  →  minimum ✓

S_min = 16 + 128/4 = 16 + 32 = 48 cm²
P2 5 marks
Q24 · Descriptive Statistics

Data: {2, 3, 5, 7, 8, 10, 12}. Tìm mean, median, Q₁, Q₃, IQR.

✓ Solution
Sum = 2+3+5+7+8+10+12 = 47
Mean = 47/7 ≈ 6.71

Median = 7 (giá trị ở giữa, n=7)
Q₁ = 3  (median của {2,3,5})
Q₃ = 10 (median của {8,10,12})
IQR = Q₃ − Q₁ = 10 − 3 = 7

APP
Phụ lục
Formula Reference
Algebra & Number
FormulaTopic
uₙ = u₁+(n−1)d · Sₙ = n/2(2u₁+(n−1)d)Arithmetic Progression
uₙ = u₁rⁿ⁻¹ · Sₙ = u₁(1−rⁿ)/(1−r) · S∞ = u₁/(1−r)Geometric Progression
(a+b)ⁿ = ∑C(n,r)aⁿ⁻ʳbʳBinomial Theorem
log rules: + − power, change of baseLogarithms
z = r cisθ · De Moivre: rⁿ cis(nθ)Complex Numbers (AA HL)
Trig & Geometry
FormulaTopic
a/sinA = b/sinB · c² = a²+b²−2ab cosCSine / Cosine Rules
Area = ½ab sinC · s = rθ · A = ½r²θArea, Arc, Sector
a·b = |a||b|cosθDot Product
sin(A±B) · cos(A±B) · double angleTrig Identities (AA)
Calculus
DerivativeIntegral
d/dx[xⁿ] = nxⁿ⁻¹∫xⁿ dx = xⁿ⁺¹/(n+1)+C
d/dx[eˣ] = eˣ∫eˣ dx = eˣ+C
d/dx[ln x] = 1/x∫1/x dx = ln|x|+C
d/dx[sin x] = cos x∫cos x dx = sin x+C
d/dx[cos x] = −sin x∫sin x dx = −cos x+C
Chain: f'(g)·g'u-substitution
Product: u'v+uv'Integration by parts (HL)
Statistics & Probability
FormulaTopic
P(A∪B) = P(A)+P(B)−P(A∩B)Probability
P(A|B) = P(A∩B)/P(B)Conditional Probability
B(n,p): E = np · Var = np(1−p)Binomial Distribution
N(μ,σ²): Z = (X−μ)/σNormal Distribution
Po(λ): E = Var = λPoisson (AI HL)
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IB Mathematics AA & AI · Practice Papers & Solutions · Song ngữ Anh–Việt
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